An ideal reversible heat engine is 1 efficient only if _.
Correct answer: D. Cold reservoir is at 0K
- A. Hot reservoir is at 0K
- B. Hot reservoir is at OC
- C. Cold reservoir is at 0C
- D. Cold reservoir is at 0K
Explanation
Efficiency of carnot engine= (1-T2/T1)*100T2=cold reservoir temp.T1=hot reservoir temp.If = (1-0/T2)*100=(1-0)*100=1*100Efficiency = 100%
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
Practise Thermodynamics
714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More First Law of Thermodynamics questions
A succession of events which bring the system back to its initial condition is called _.
Which of the following statement is not true about heat engine?
When the amount of work done is 333 cal and internal energy is 167 cal then heat supplied is _.
The energy input to an engine is 60 J, and the work it performs is 15 J. What fraction of the energy input is expelled to the cold reservoir?
If heat given is 6 kcal and work done is 6 kJ, then internal energy is _.
Which of these is constant in isothermal process?