An evaporator while concentrating an aqueous solution from 10 to 40% solids evaporates 30000 kg of water. The amount of solids handled by the system in kg is___________________?
Correct answer: A. 4000
- A. 4000
- B. 9000
- C. 4600
- D. 3000
Explanation
Let the unchanged solids mass be S. Initial water is 9S and final water is 1.5S because the final solution contains 40% solids, so 9S − 1.5S = 30,000, giving S = 4,000 kg.
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