An elevator initially accelerates upward from rest and then ascends with uniform speed. The time period of a simple pendulum in the elevator will:
Correct answer: B. Decrease and then increase
- A. Increase and then decrease
- B. Decrease and then increase
- C. Increase
- D. Decrease
Explanation
In an elevator that initially accelerates upward from rest and then ascends with uniform speed, the effective gravitational force experienced by the simple pendulum inside the elevator will change. During the initial acceleration, the effective gravitational force will be greater than g. As a result, the time period of the simple pendulum will be shorter because the effective acceleration acting on the pendulum is greater. Once the elevator reaches a constant speed, the effective gravitational force will return to g, and the time period of the simple pendulum will return to its original value. Hence B is the correct option.
Last updated
Related questions
A 2 kg body falls from infinity to the surface of earth. What will be the kinetic energy of the body on reaching the surface of Earth (Assume escape velocity to be 104 ms-1)?
A bird resting on the floor of an air-tight box which is being carried by a boy, starts flying. The boy will feel that the box is now:
A body in satellite orbiting round the earth is weightless because:
A body is taken from the earth's surface to the moon, the weight of the body will be zero at a point where force of attraction due to:
A body of 2kg is suspended from the ceiling of an elevator moving up with an acceleration 'g' its apparent weight in the elevator will be: