An electron of charge e is introduced between two metal plates a distance d apart. A potential difference V is applied to the plates as shown in the diagram.Which expression gives the electric force F on the electron?
Correct answer: A. eV/d
- A. eV/d
- B. eVd
- C. V/ed
- D. dV/e
Explanation
The electric field E between parallel plates is V/d. The force on a charge q in an electric field E is given by F = qE, so for an electron with charge e, F = eE = eV/d.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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