An electron is travelling with a velocity of 106 m/s, perpendicular to a field of strength 1 W/m2. The magnetic force on the electron will be (Note: Take the charge of an electron as 1.6 x 10^-19 C.)
Correct answer: B. 1.6 x 10^-13 N.
- A. 1.6 x 10^-25 N.
- B. 1.6 x 10^-13 N.
- C. 1.6 x 10^13 N.
- D. 1.6 x 10^25 N
Explanation
The magnetic force on a charged particle moving perpendicular to a magnetic field is calculated using the formula F = qvB, where q is the charge, v is the velocity, and B is the magnetic field strength. Here, q = 1.6 × 10-19 C, v = 106 m/s, and B = 1 W/m2. Substituting these values, the force F is calculated as 1.6 × 10-13 N, which is the correct choice (Option B). Options A, C, and D are incorrect as they result from calculation errors, either underestimating or overestimating the magnitudes.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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