An electron is moving with a kinetic energy of 4.55 x 10^-25J. What will be the de Broglie wave length for this electron?
Correct answer: B. 7.28 x 10^-7m
- A. 5.28 x 10^-27m
- B. 7.28 x 10^-7m
- C. 2 x 10^-10m
- D. 3 x 10^-5m
Explanation
The de Broglie wavelength (λ) of a particle is given by the formula λ = h / p, where h is the Planck constant and p is the momentum of the particle. For an electron, the momentum can be related to its kinetic energy (K) as p = √(2mK), where m is the mass of the electron. Given the kinetic energy K = 4.55x10-25 J, the mass of an electron (m), and the Planck constant (h), the calculated de Broglie wavelength is indeed 7.28x10-7 m.
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