An electron having following set of values lies in: n = 4, l= 0, m = 0 & s = -1/2

Correct answer: A. 4s

  • A. 4s
  • B. 4p
  • C. 5s
  • D. 5p

Explanation

n equal to 4 gives the fourth shell and l equal to 0 gives an s subshell, so the electron is in 4s, with m equal to 0 the only value allowed for an s orbital. A p subshell would need l equal to 1, and 5s or 5p would need n equal to 5.

This question appeared on the UHS MDCAT 2026 paper, which you can sit online with every answer explained.

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