An electrician is supposed to measure an AC voltage in a common household wiring. If his voltmetre measures 220 V in the wiring, then its peak value of the voltage will be
Correct answer: A. 314.2 V
- A. 314.2 V
- B. 220.0 V
- C. 154.0 V
- D. 110.0 V
Explanation
The correct answer is Option A: 314.2 V. The peak value of an AC voltage is √2 times the RMS value. In this case, multiplying 220 V by √2 gives approximately 314.2 V. The other options are incorrect because they either provide the RMS value, a lower peak value, or a significantly lower peak value, which does not align with the relationship between peak and RMS values for AC voltages.
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Alternating current through a resistor, capacitor and inductor involves phase relationships between voltage and current, reactance, impedance and energy transfer. A resistor keeps voltage and current in phase, while a capacitor and inductor produce opposite phase shifts, a distinction used in circuit diagrams and numerical calculations.
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