An ammeter has a resistance of G ohms and range of I amperes. The value of resistance required in parallel to convert it into an ammeter of range nI is______________?
Correct answer: C. G/(n-1)
- A. nG
- B. (n-1)G
- C. G/(n-1)
- D. G/n
Explanation
The meter carries its original full-scale current I, while the parallel shunt carries (n − 1)I. Equal voltage drops give IG = (n − 1)I R_sh, hence R_sh = G/(n − 1).
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