An alternating current '1/A' varies with time 't/s' according to the equation I = 5sin(100πt). What is the mean power developed by the current in a resistive load of resistance 10?
Correct answer: A. 125W
- A. 125W
- B. 160W
- C. 250W
- D. 500W
Explanation
To find the mean power developed by the current in the resistive load, we first calculate the peak value of the current, which is 3.53. With a resistance of 10Ω, the power is determined using P = I²R = (3.53)²(10) = 125 W. The correct answer is 125W. The other options are incorrect because they do not accurately reflect the power calculated based on the values provided in the question.
This question appeared on the ETEA MDCAT 2013 paper, which you can sit online with every answer explained.
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About AC Through Resistor, Capacitor and Inductor
Alternating current through a resistor, capacitor and inductor involves phase relationships between voltage and current, reactance, impedance and energy transfer. A resistor keeps voltage and current in phase, while a capacitor and inductor produce opposite phase shifts, a distinction used in circuit diagrams and numerical calculations.
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