An alternating current '1/A' varies with time 't/s' according to the equation I = 5sin(100πt). What is the mean power developed by the current in a resistive load of resistance 10?
Correct answer: A. 125W
- A. 125W
- B. 160W
- C. 250W
- D. 500W
Explanation
To find the mean power developed by the current in the resistive load, we first calculate the peak value of the current, which is 3.53. With a resistance of 10Ω, the power is determined using P = I²R = (3.53)²(10) = 125 W. The correct answer is 125W. The other options are incorrect because they do not accurately reflect the power calculated based on the values provided in the question.
Last updated
About AC Through Resistor, Capacitor and Inductor
Alternating current through a resistor, capacitor and inductor involves phase relationships between voltage and current, reactance, impedance and energy transfer. A resistor keeps voltage and current in phase, while a capacitor and inductor produce opposite phase shifts, a distinction used in circuit diagrams and numerical calculations.
Practise Alternating Current
592 free Alternating Current MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
In a purely resistive AC circuit, the current and the voltage are
In a purely capacitive AC circuit, the current
The capacitive reactance of a capacitor
The inductive reactance of a coil is given by
The average power dissipated in a purely inductive or purely capacitive AC circuit over a complete cycle is