An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is:.
Correct answer: C. 3.33 km
- A. 1200 m
- B. 0.33 m
- C. 3.33 km
- D. 33 km
Explanation
The correct option is C: 3.33 km.When the bomb is released, it has a horizontal velocity of 600 km/h and a vertical velocity of 0. By applying the formula for projectile motion, we can calculate that the bomb will strike the ground at a horizontal distance of 3.33 km from the release point.The other options are incorrect because they either ignore the horizontal velocity of the airplane, miscalculate the time of flight, or do not consider both the horizontal and vertical components of motion.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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