Ammonia react with borontrifluoride & form coordinate covalent bond with BF₃ in this reaction ammonia donate lone pair of electron to
Correct answer: C. Vacant 2p orbital's of boron
- A. Vacant sp³ hybrid orbital of boron
- B. Half filled sp³ hybrid orbital of boron
- C. Vacant 2p orbital's of boron
- D. Vacant sp² hybrid orbital of boron
Explanation
The reaction between ammonia and boron trifluoride involves the formation of a coordinate covalent bond, where ammonia donates its lone pair of electrons to boron. In BF₃, boron is sp² hybridized, which means there are three sp² hybrid orbitals and one vacant 2p orbital. The vacant 2p orbital of boron is the one that accepts the lone pair of electrons from ammonia, forming the coordinate bond. Options A and B are incorrect because they refer to sp³ orbitals, which are not present in BF₃. Option D is incorrect because although BF₃ is sp² hybridized, the lone pair is donated to the unhybridized 2p orbital, not a hybrid orbital.
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