Air/fuel ratio on molar (volume) basis for combustion of methane with theoretical quantity of air with be________________?
Correct answer: A. 9.5 : 1
- A. 9.5 : 1
- B. 12.5 : 1
- C. 15.5 : 1
- D. 18.5 : 1
Explanation
Methane requires 2 mol of oxygen per mole: CH₄ + 2O₂ → CO₂ + 2H₂O. Since air contains about 4.76 mol of air per mole of oxygen, the theoretical air requirement is 2 × 4.76 ≈ 9.5 mol air per mol methane.
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