According to Chilton-Colburn analogy for mass transfer, NSt.NSc 2/3 is equal to_________________?
Correct answer: B. f/2
- A. f
- B. f/2
- C. 2f
- D. 1/f
Explanation
The Chilton-Colburn analogy equates the mass-transfer j-factor, St_m Sc^(2/3), to half the Fanning friction factor, f/2. Confusing Fanning and Darcy friction factors commonly produces a factor-of-two error.
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