According to Bond crushing law, the work required to form particle of size 'D' from very large feed is (where (S/V)p and (S/V)f are surface to volume ratio of the product and feed respectively) ?
Correct answer: D. √(S/V)p
- A. (S/V)p
- B. (S/V)f
- C. (S/V)2p
- D. √(S/V)p
Explanation
Bond's law makes work proportional to the difference in the reciprocals of the square roots of feed and product sizes. For a very large feed, the feed term approaches zero, leaving work proportional to √(S/V)p.
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