According to Bond crushing law, the work required to form particle of size 'D' from very large feed is (where (S/V)p and (S/V)f are surface to volume ratio of the product and feed respectively) ?
Correct answer: B. √(S/V)p
- A. (S/V)p
- B. √(S/V)p
- C. (S/V)2p
- D. (S/V)f
Explanation
Bond's law makes work proportional to the difference in the reciprocals of the square roots of feed and product sizes. For a very large feed, the feed term approaches zero, leaving work proportional to √(S/V)p.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
Practise Chemical Process Principles
2,710 free Chemical Process Principles MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Process Principles questions
Which of the following is not a revolving/tumbling mill used for size reduction ?
Reduction ratio of crushers is the___________________?
_____________ are mixed using ribbon blenders ?
Vibrating screens are used for handling large tonnages of materials. The vibrating motion is imparted to the screening surface by means of_____________________?
Number of particles in a crushed solid sample is given by (where, m = mass of particles in a sample, Vp = volume of one particle, ρ= density of particles) ?
Ultrafine grinders operate principally by_________________?