A zirconium nucleus is a ß-emitter. The product nucleus is also a ß-emitter. What is the final resulting nucleus of these two decays?
Correct answer: B. 100Mo42
- A. 100Sr38
- B. 100Mo42
- C. 98Zr40
- D. 100Zr40
Explanation
In beta decay, mass number reamins the same but proton number increases by 1. Since there are 2 beta decays, proton number will be increased by 2.Zirconium has 40 protons so proton number will increases from 40 t0 42. Thus option B is correct.
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