A yellow light of wavelength 500 nm emitted by a single source passes through two narrow slits 1 mm apart. How far apart are two adjacent bright fringes when interference is observed on a screen 10 m away?
Correct answer: A. 5 mm
- A. 5 mm
- B. 1.33 mm
- C. 0.5 mm
- D. 50 mm
Explanation
x=λ D/a, where λ is the wavelength of light, D is the distance between screen and slits, a is the slit separation, and x is the fringe separation, all measured in metres. λ =500nm=500×10ˆ-9 m D=10m a=1mm=1×10ˆ-3 m x=500×10ˆ-9×10/1×10ˆ-3 x=5×10ˆ-3 x=5mm
This question appeared on the UHS MDCAT 2008 paper, which you can sit online with every answer explained.
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About Superposition and Interference
Superposition states that overlapping waves produce a resultant displacement equal to the algebraic sum of their individual displacements. Interference covers constructive and destructive interference, phase difference, path difference, coherent sources, and conditions for maxima and minima. It differs from diffraction, which involves spreading around openings or obstacles.
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