A wire of length L is stretched by a length l when a force F is applied at one end. If the elastic limit is not exceeded, the amount of energy stored in the wire is
Correct answer: B. 1/2Fl
- A. Fl
- B. 1/2Fl
- C. Fl^2 /L
- D. 1/2fl^2
Explanation
The amount of energy stored in an elastic material when stretched is given by the formula 1/2 * force * extension. In this case, the force is F and the extension is l. Therefore, the energy stored in the wire is 1/2 * (F * l).
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