A wire of length 2m is attached with mass of 5kg vertically, tensile strain of wire is 0.3 x 10^-3, the extension in wire is:
Correct answer: D. 0.6mm
- A. 1.5mm
- B. 2mm
- C. 0.15mm
- D. 0.6mm
Explanation
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl. strain= Δl/L Δl =strain x L =0.3x10-³ x 2 =0.6x10-³ =0.6mm ANS
This question appeared on the UHS MDCAT 2017 paper, which you can sit online with every answer explained.
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Deformation and elasticity describe how solids change shape or volume under an applied force and return to their original form when the force is removed. Work includes stress, strain, Hooke’s law, elastic limit, Young’s modulus and elastic potential energy, while elastic deformation must be distinguished from permanent plastic deformation.
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