A wire of length 2m is attached with mass of 5kg vertically, tensile strain of wire is 0.3 x 10^-3, the extension in wire is:
Correct answer: D. 0.6mm
- A. 1.5mm
- B. 2mm
- C. 0.15mm
- D. 0.6mm
Explanation
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl. strain= Δl/L Δl =strain x L =0.3x10-³ x 2 =0.6x10-³ =0.6mm ANS
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