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A wire of length 2m carries a current of 10A. What is the force acting on it when it is placed at an angle of 45o to the uniform magnetic field of 0.15T?

Correct answer: D. 3/√ 2N

  • A. 1.2N
  • B. 3.2N
  • C. 2.5N
  • D. 3/√ 2N

Explanation

Using the formula F = BIL sinθ Where, B = Magnetic field strength = 0.15T I = Current = 10A L = Length of the conductor = 2m θ = Angle between the conductor and magnetic field = 45° F = 0.15 x 10 x 2 x sin45 (substituing sin45 = 1/√2) F = 1.5 x 2 x 1/√2 F = 3 x 1/√2 F = 3/√2 You can use the following table to memorize important values for sin cos and tan to boost your calculation speed!

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About Electromagnetism

Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.

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