A wire has a resistance 'R'. If its length is doubled and radius is reduced to half then its resistance will become:

Correct answer: C. 8R

  • A. 2R
  • B. 4R
  • C. 8R
  • D. 16R

Explanation

To determine the new resistance, use the formula Resistance = resistivity × length/area. When the length is doubled, the resistance is also doubled (2R). Reducing the radius to half causes the cross-sectional area (πr²) to become one quarter, which increases the resistance by a factor of four (4R). Therefore, the new resistance is 2 × 4 = 8R. Options 2R and 4R underestimate the effect of reducing the radius, while 16R overestimates it.

This question appeared on the ETEA MDCAT 2013 paper, which you can sit online with every answer explained.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Resistance and Resistivity

Resistance measures opposition to current in a conductor and follows R = V/I for an ohmic conductor, while resistivity is an intrinsic property of the material. Questions use R = ρL/A, examine effects of length, cross-sectional area and temperature, and distinguish resistance, resistivity, conductance and conductivity.

Practise Current Electricity

1,052 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Resistance and Resistivity questions