A wire has a resistance of 5.5 Ω at 19°C and 21.5 Ω at 200°C. Find the temperature coefficient of resistivity(α) of the material.
Correct answer: A. 0.016 per degree celsius
- A. 0.016 per degree celsius
- B. 32 per degree celsius
- C. 0.018 per degree celsius
- D. 0.00106 per degree Celsius
Explanation
The temperature coefficient of resistivity (α) is given by the formula: α = (R2 - R1) / (R1 x (T2 - T1)) where R1 is the resistance at temperature T1, R2 is the resistance at temperature T2, and alpha is the temperature coefficient of resistivity. Substituting the given values, we get: α = (21.5 - 5.5) / (5.5 x (200 - 19) = 0.016per degree Celsius Therefore, the temperature coefficient of resistivity of the material is 0.016 per degree Celsius.
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