A voltage divider consists of two 100 kΩ resistors and a 12 V source. What will the output voltage be if a load resistor of 1 MΩ is connected to the output?

Correct answer: D. 5.7 V

  • A. 0.57 V
  • B. 6 V
  • C. 12 V
  • D. 5.7 V

Explanation

The load changes the lower 100 kΩ resistor to 100 kΩ || 1 MΩ = 90.9 kΩ. The loaded divider output is 12 × 90.9/(100 + 90.9), approximately 5.7 V.

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