A voltage divider consists of two 100 kΩ resistors and a 12 V source. What will the output voltage be if a load resistor of 1 MΩ is connected to the output?
Correct answer: D. 5.7 V
- A. 0.57 V
- B. 6 V
- C. 12 V
- D. 5.7 V
Explanation
The load changes the lower 100 kΩ resistor to 100 kΩ || 1 MΩ = 90.9 kΩ. The loaded divider output is 12 × 90.9/(100 + 90.9), approximately 5.7 V.
Last updated
Practise Circuit Analysis
394 free Circuit Analysis MCQs from Electrical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Electrical Engineering questions like this
Electrical Engineering is on 2 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
74. Sparking occurs when a load is switched off because the circuit has high_________?
A 12 kΩ resistor, a 15 kΩ resistor, and a 22 kΩ resistor are in series with two 10 kΩ resistors that are in parallel. The source voltage is 75 V. Current through the 15 kΩ resistor is approximately___________?
A 200 turn coil has an inductance of 12 mH. If the number of turns is increased to 400 turns, all other quantities (area, length etc.) remaining the same, the inductance will be___________?
A 3 Q resistor having 2 A current will dissipate the power of_______________?
A 40 W bulb is connected in series with a room heater. If now 40 W bulb is replaced by 100 W bulb, the heater output will__________