A Uranium isotope 92U232 undergoes one α-decay and two β-1 - decay. What is the final product?
Correct answer: B. 92
- A. 90
- B. 92
- C. 89
- D. 88
Explanation
Alpha decay causes a decrease in atomic number by 2 and mass number by 4. One beta decay causes increases in atomic number by one while the mass number remains the same. Since there are two beta-decay the atomic numbers increase by two making the atomic number back to 92.It is numerical and can have only one possible answer.
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