A U-tube in which the cross-sectional area of the limb on the left is one-quarter, and the limb on the right contains mercury (density 13.6 g/cm3). The level of mercury in the narrow limb is at a distance of 36 cm from the upper end of the tube. What will be the rise in the level of mercury in the right limb if the left limb is filled to the top with water?
Correct answer: C. 0.56 cm
- A. 1.2 cm
- B. 2.35 cm
- C. 0.56 cm
- D. 0.8 cm
Explanation
To solve this problem, we use the principle of fluid statics. When water is added to the left limb, it applies pressure that causes the mercury in the right limb to rise. The pressure exerted by the water column is balanced by the pressure due to the rise in mercury in the right limb. The relationship is given by the formula:Pressure by water = Pressure by mercury.Considering the cross-sectional area difference and the densities, we find that the rise in mercury level in the right limb is 0.56 cm. The other options do not correctly account for the density and cross-sectional area differences, leading to incorrect calculations.
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