A tuning fork A produces 4 beats / second with another turning fork B of frequency 280 Hz. When fork A is loaded with a little wax, the beat frequency change to 2. The frequency of fork A before loading is:
Correct answer: B. 284 Hz
- A. 292 Hz
- B. 284 Hz
- C. 290 Hz
- D. 288 Hz
Explanation
Beat frequency is given by the equation; Beat frequency = f1-f2Whereas f1 is AAnd f2 is BSince the frequency of the B tuning fork is 280 Hz and the number of beats per second before applying wax is 4. Therefore,4-f1-280F1-4+280 F1/A is 284Hz.As it is a numerical, it can have only one possible answer.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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