A tube closed at one end and containing air produces, when excited, the fundamental note of frequency 512Hz. If the tube is open at both ends, the fundamental frequency that can be excited is (Hz).
Correct answer: A. 1024
- A. 1024
- B. 512
- C. 256
- D. 128
Explanation
The fundamental frequency of a tube closed at one end is given by:f = v / 4LWhere v is the speed of sound in air, and L is the length of the tube.In this case, f = 512 Hz, so v = 4L x 512 = 2048L.The fundamental frequency of a tube open at both ends is given by:f = v / 2LSubstituting v = 2048L, we get:f = 2048L / 2L = 1024 Hz
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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