A transistor is connected in a common emitter configuration. The collector supply is 8V and the voltage drop across a resistor of 800Ω in the collector circuit is 0.5 V. If the current gain factor α is 0.96, then the base currents are:
Correct answer: B. 26µA
- A. 20µA
- B. 26µA
- C. 30µA
- D. 35µA
Explanation
α = 0.96 β = α / 1 - α ==> 0.96 / 1 - 0.96 = 24 Ic = Vc / Rc Ic = 0.5 / 800 = 6.25 x 10-4 β = Ic / Ib Ib (base current) = 6.25 x 10-4 / 24 Ib = 26 µA
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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