A transformer has N2/N1 = 10, the load current is 1.0A, the current in primary is:
Correct answer: D. 10 A
- A. 1A
- B. 0.1 A
- C. 11 A
- D. 10 A
Explanation
The turns ratio (N2/N1) of a transformer is the ratio of the number of turns in the secondary coil (N2) to the number of turns in the primary coil (N1).Given N2/N1 = 10, and the load current is 1.0A, the current in the primary (I1) can be calculated using the formula:I1/I2 = N2/N1where I1 is the primary current, I2 is the secondary current.In this case, ( I1/1.0A = 10 ), which implies ( I1 = 10A ).Therefore, the correct option is: D. 10 A
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Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
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