A total of 300 tickets were sold for a performance of a school play. The ticket prices were $5 for each adult and $3 for each child, and the total revenue from tickets was $1,400. Solving which of the following systems of equations would yield the number of adult tickets sold, a, and the number of children's tickets sold, c?
Correct answer: B. a + c = 300 5a + 3c = 1400
- A. a + c = 1,400 5a + 3c = 300
- B. a + c = 300 5a + 3c = 1400
- C. a + c = 300 3a + 5c = 1,400
- D. a + c = 300 3a + 5c = 1,400 × 2
Explanation
Using the equations in Option B, the number of tickets for adults and child sold can be found out A being the number of Adults C being the number of children A+C= 300 (1) A= 300-C 5A+3C=1400 (2) Substituting A in equation 2 5(300-C) +3C=1400 1500-5C+3C=1400 1500-1400=2C 100/2=C C=50 A+C=300 A+50=300 A=300-50 A=250 Tickets sold for ADULT=250 Tickets sold for CHILDREN=50 All the other options do not consist of sufficient option to find the actual number of tickets sold to Adults and children
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