A total of 300 tickets were sold for a performance of a school play. The ticket prices were $5 for each adult and $3 for each child, and the total revenue from tickets was $1,400. Solving which of the following systems of equations would yield the number of adult tickets sold, a, and the number of children's tickets sold, c?
Correct answer: B. a + c = 300 5a + 3c = 1400
- A. a + c = 1,4005a + 3c = 300
- B. a + c = 300 5a + 3c = 1400
- C. a + c = 3003a + 5c = 1,400
- D. a + c = 3003a + 5c = 1,400 × 2
Explanation
To solve this problem, set up the system of equations based on the information provided: a + c = 300 and 5a + 3c = 1,400. Option B correctly establishes these equations, allowing you to find the number of adult and children's tickets sold. By solving these equations simultaneously, the correct values of a = 250 and c = 50 are obtained. This results in 250 adult tickets and 50 children's tickets being sold. The other options fail to provide the correct equations, leading to inaccurate conclusions.
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