A thin horizontal plate of area 0.036 m2 is beneath the surface of a liquid of density 930 kg m−3. The force on one side of the plate due to the pressure of the liquid is 290 N. What is the depth of the plate beneath the surface of the liquid?
Correct answer: A. 0.88 m
- A. 0.88 m
- B. 1.1 m
- C. 1.8 m
- D. 8.7 m
Explanation
Pressure P = hρgwhere h is the depth, ρ is the density of the liquid and g is the acceleration of free fall.But,Pressure P = Force / Area = F / ATherefore,Depth h = P / ρg = F / (Aρg) = 290 / [0.036 (930) (9.81)] = 0.88m
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