A string of length 2m fixed between two supports vibrates in two loops. The distance between node and antinode is:
Correct answer: A. 50 cm
- A. 50 cm
- B. 200 cm
- C. 100 cm
- D. 10 cm
Explanation
The string, with a length of 2 meters, vibrates in two loops. This means each loop is 1 meter long. The distance between a node and an antinode is half the length of one loop, which is 50 cm. Therefore, the correct answer is Option A: 50 cm. Option B is incorrect because 200 cm is the total length of the string. Option C is incorrect as 100 cm is the length of one loop, not the distance between a node and an antinode. Option D is incorrect because 10 cm is too short to be the correct distance in this context.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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