A string clamped at its both ends, vibrates in four segments (loops). The length of string is 150cm. The wavelength of the wave is:
Correct answer: D. 75 cm
- A. 33.3 cm
- B. 66.7 cm
- C. 150 cm
- D. 75 cm
Explanation
The length of the string is 150 cm and it vibrates in four segments. Each segment corresponds to half a wavelength, so the total length of the string represents two wavelengths. Therefore, the wavelength can be calculated using the formula:wavelength = (length of string) / (number of segments / 2)Substituting the given values, we get:wavelength = 150 cm / (4 / 2) = 150 cm / 2 = 75 cm
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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