A stone to the end of a string 1m is whirled ina horizontal circle with a constant speed. If the stone makes 22 revolution in 44 seconds, What is the magnitude and direction of a acceleration of the stone.
Correct answer: B. π2ms-2 and direction along the radius towards the centre
- A. π2/4ms-2 and direction along the radius towards the centre
- B. π2ms-2 and direction along the radius towards the centre
- C. π2ms-2 and direction along the radius away from the centre
- D. π2ms-2 and direction along the tangent to the circle
Explanation
a=v²/r = ω²r = 4π²n²r = 4π² (22/44)² × 1 = π²m/s², and its direction is always along the radius and towards the centre. In uniform circular motion, the acceleration (centripetal acceleration) is always directed along the radius towards the centre of the circular path.
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