A stone of mass m tied to a string of length I. It is rotated in a circle with the other end of the string as the centre. The speed of the stone is v. If the string breaks, the stone will move
Correct answer: C. Along the tangent
- A. Toward the centre of circle
- B. Away from centre of circle
- C. Along the tangent
- D. All of these
Explanation
Option C is correct.If the string breaks, the stone will move in a straight line tangent to the circle that it was rotating in. This is because the stone will no longer be subject to the centripetal force that was keeping it in a circular path. The centripetal force is given by the following equation: F = mv²/r where: F is the centripetal force (N) m is the mass of the stone (kg) v is the speed of the stone (m/s) r is the radius of the circle (m) When the string breaks, the centripetal force will be zero, and the stone will move in a straight line tangent to the circle.
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About Angular and Linear Quantities
Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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