Asked in MDCAT Test Series — Electrostatics, Work and EnergyModerate

A stone is thrown up from the surface of the Earth when it reaches at maximum height, its K.E. is equal to:

Correct answer: B. Zero

  • A. mgh
  • B. Zero
  • C. 1/2 mv2
  • D. 2mgh

Explanation

Ooption B is corrrect.The kinetic energy (KE) of a stone is equal to zero at its maximum height. This is because the stone is not moving at that point. The stone's kinetic energy is converted into potential energy as it rises, and all of its kinetic energy is converted into potential energy at its maximum height. Here is a mathematical explanation: The kinetic energy of a stone is defined as the energy that it has due to its motion. The kinetic energy of a stone is measured in joules. The formula for kinetic energy is: KE = (1/2)mv² where: m is the mass of the stone v is the velocity of the stone When the stone reaches its maximum height, its velocity is zero. This means that the kinetic energy of the stone is also zero. Here is an example: Suppose a stone of mass 1 kg is thrown up from the surface of the Earth with an initial velocity of 10 m/s. The kinetic energy of the stone at the point of release is: KE = (1/2)mv² = (1/2) * 1 kg * 10 m/s² = 50 J As the stone rises, its kinetic energy is converted into potential energy. The potential energy of the stone is given by the following formula: PE = mgh where: m is the mass of the stone g is the acceleration due to gravity h is the height of the stone above the ground At the maximum height, the stone's velocity is zero and its height is h. This means that the kinetic energy of the stone is zero and the potential energy of the stone is equal to the initial kinetic energy of the stone. PE = mgh = 50 J Therefore, the kinetic energy of the stone is equal to zero at its maximum height.

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