A stationary wave is setup on a string of length 10 cm. Four loops are formed. What is the distance between two consecutive antinode?
Correct answer: C. 2.5 cm
- A. 4.5 cm
- B. 5 cm
- C. 2.5 cm
- D. 1.25 cm
Explanation
Loops of stationary waves consists of nodes and antinodes . The distance between two consective antinodes (crest) or nodes (trough) is equal to 1 wavelength , same is the case with two consecutive crest or trough so when 10cm the total lenght is divided, n=4 (given), then one wavelenght comes out which is 2.5 cm.
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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