Asked in PMC Practice Test 3 (2022) 2022

A stationary wave is set up on a string of length 10 cm. Four loops are formed. What is the distance between two consecutive crests?

Correct answer: B. 5 cm

  • A. 4.5 cm
  • B. 5 cm
  • C. 2.5 cm
  • D. 1.25 cm

Explanation

In a stationary wave, the distance between two consecutive crests (or troughs) is known as the wavelength (λ). The wavelength is related to the length of the string (L) and the number of loops (n) formed on the string by the following formula:λ = 2L / nwhere:λ = wavelengthL = length of the stringn = number of loops (or antinodes) formed on the stringIn this case, the length of the string (L) is given as 10 cm, and the number of loops (n) formed is 4.Let's calculate the wavelength:λ = 2 * 10 cm / 4λ = 20 cm / 4λ = 5 cmSo, the distance between two consecutive crests (wavelength) in this stationary wave is 5 cm.

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About Stationary Waves

Stationary waves form when two waves of the same frequency and amplitude travel in opposite directions and interfere. The topic covers nodes, antinodes, wavelength, phase, resonance, and the allowed frequencies on strings and in air columns. Unlike progressive waves, stationary waves do not transfer energy from one point to another.

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