A standing wave in a closed pipe (one end closed) has a length of 0.5 m. What is the wavelength of the second harmonic? (Speed of sound = 343 m/s)
Correct answer: C. 1.33 m
- A. 0.67 m
- B. 1.0 m
- C. 1.33 m
- D. 2.0 m
Explanation
For a closed pipe, second harmonic wavelength λ2 = 4L / 3 = (4 × 0.5) / 3 = 2 / 3 ≈ 1.33 m.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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