A sphere of charge +Q is fixed in a position. A smaller sphere of charge +q is placed near the larger sphere and released from rest. The small sphere will move away from the large sphere with:

Correct answer: C. Increasing velocity and decreasing acceleration

  • A. Decreasing velocity and increasing acceleration
  • B. Decreasing velocity and constant acceleration
  • C. Increasing velocity and decreasing acceleration
  • D. Increasing velocity and increasing acceleration

Explanation

When the smaller charge is placed, it undergoes repulsion as 'like' charges repel. Since it was at zero velocity, the velocity increases. But as the charge moves further away, the force of repulsion decreases, and according to the formula, F= kQq/r2, acceleration decreases.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Electrostatics

Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.

Practise Electrostatics

833 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Electrostatics questions