A sound wave has a wavelength of 0.20 m. What is the phase difference between two points along the wave which are 0.65 m apart?
Correct answer: C. 900
- A. 00
- B. 450
- C. 900
- D. 1800
Explanation
λ= 0.20m.Phase difference= 0.65mNearest integral multiple of wavelength to phase difference= 0.20 x 3= 0.60mNet phase difference = 0.65 - 0.60= 0.05mIn degrees = (phase difference/wavelength) x360= (0.05/0.20) x 360= 90 degrees
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