A simple pendulum completes one oscillation in 4 seconds. Calculate its length when g= 9.8 m/s2, as the time period of a simple pendulum is given by T = 2 π √(l/g)
Correct answer: A. 3.973 m
- A. 3.973 m
- B. 5.123 m
- C. 7.111 m
- D. 9.231 m
- E. 12.141 m
Explanation
To find the length of the pendulum, use the formula for the time period of a simple pendulum: T = 2π√(l/g). Given that T = 4 s and g = 9.8 m/s², rearrange the formula to solve for l:l = (T²g)/(4π²).Substitute the given values:l = (4² × 9.8)/(4 × π²) ≈ 3.973 m.Therefore, the correct length is approximately 3.973 meters. Other options result from errors in rearranging the formula or incorrect substitution of values.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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