A simple pendulum completes one oscillation in 4 seconds. Calculate its length when g= 9.8 m/s2, as the time period of a simple pendulum is given by T = 2 π √(l/g):
Correct answer: A. 3.973 m
- A. 3.973 m
- B. 5.123 m
- C. 7.111 m
- D. 9.231 m
Explanation
This option uses the correct application of the formula T = 2π√(l/g) and solves for l using the given values, resulting in the length of approximately 3.973 meters.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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