a simple harmonic oscillator has period of 0.01 second and amplitude of 0.2 m. the magnitude of the velocity in m/s at the center of oscillation is
Correct answer: D. 40π
- A. 100
- B. 100π
- C. 20π
- D. 40π
Explanation
Given:Period (T) = 0.01 sAmplitude (A) = 0.2 mWe know for simple harmonic motion,Velocity (v) at the centre = A * ωWhere, ω = 2π/Tω = 2π/0.01 = 200π rad/sv = A * ω= 0.2 * 200π= 40π m/sThe magnitude of velocity at the center of oscillation is 40π m/s.The answer is d
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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