A ship of mass 3 x 10^7kg initially at rest is pulled by a force of 5 x 10^4N through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is?
Correct answer: C. 0.1m/s
- A. 1.5 m/s
- B. 60 m/s
- C. 0.1m/s
- D. 5 m/s
Explanation
Step 1: Acceleration of the ship, Applying Newton's law, F=maa= m/F = 5×10 4/3×10 7 = 5/ ×10−3 m/s2Step 2: Final speed of the shipUsing 3rd equation of motion,v2−u2 =2as v2−02 =2×5/3×10−3 m/s2 ×3mv2 =10−2v=0.1m/sHence, option (C) is correct.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Force and Motion questions
A body of mass m=3.513kg is moving along the x-axis with a speed of 5.00 ms-1. The magnitude of its momentum is recorded as:
Two blocks of masses 2 kg and 4 kg are hanging with the help of a massless string passing over an ideal pulley inside an elevator. The elevator is moving upward with an acceleration of g/2. The tension in the string connected between the blocks will be (Take g = 10m/s2):
A string of length L is fixed at one end and carries mass M at the other end. It is rotated around a vertical axis as shown in figure. Net force on the mass M is:
The instantaneous accelaration is the limit of average acceleration as Δ→ 0 is given by:
The length of the of a particle is equal to the magnitude of the displacement of that particle. Shape of the path possible is:
A man is in a car is moving with velocity of 36 km/hr. His speed with respect to the car is: