A satellite moves in the circle orbit at the constant speed under the action of the gravitational force of a planet. The work done on the satellite in one revolution will have magnitude:
Correct answer: A. Zero
- A. Zero
- B. Half of the gravitational pull of the planet
- C. Equal to the gravitational pull of the planet
- D. Proportional to the diameter of the orbit
Explanation
A is the correct answer. In a circular orbit, the gravitational force is acting perpendicular to the direction of motion of the satellite. The work done by a force is given by the formula W= F ⋅ d, where F is the force, and d is the displacement. Since the gravitational force and the displacement are perpendicular, the dot product is zero, and the work done is zero.
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