A rope of length 5 m is kept on a frictionless surface and a force of 5 N is applied to one of its ends. What is the tension in the rope at 1 m from this end?
Correct answer: D. 4N
- A. 1N
- B. 5N
- C. 3N
- D. 4N
Explanation
Force applied on the rope = 5 N Length of the rope = 5 m Assume x = mass of the rope. If mass of full 5 meters = x, then mass of 1 meter = x / 5 F = ma (where F = force, m = mass, a = acceleration) Acceleration of the rope = a = F / m = 5 / x At 1 meter from the end where the force is applied, tension then acts on the remaining 4 meters Mass of the 4 meters of rope = 4x / 5 Tension in 4 meters of rope = ma = (4x/5) (5/x) = 4 N
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