A rock climber is climbing up a 450 feet high cliff. By 9:30 AM. the climber reached 90 feet up the cliff and by 11:00 AM he has reached 210 feet up the cliff. If he climbs with a constant speed, by what time will he reach the top of the cliff?
Correct answer: B. 2:00 PM
- A. 1:45 PM
- B. 2:00 PM
- C. 2:15 PM
- D. 2:30 PM
Explanation
Constant speed is equal distance covered in equal time periods So he will cover the rest of the distance by the same time intervals as before Distance covered : 210 ft As we have the time interval from 9: 30 to 11:00 A.M we will use the distance covered in this interval only in the ratio method Distance covered in interval 9 : 30 to 11:AM 210 - 90= 120 ft Distance remaining : 450 - 210=240 So using ratio method Ft./hrs 120/1.5=240/ x Cross multiplying =120 * x=1.5 * 240 x = 3 hrs 3 hrs is the time interval between 11 and the reaching time of the climber. So, Reaching time - option =3 hrs (converting in 24 hour clock before subtraction by adding 12 to the options) Option A) =12:00+ 1 : 45 =13 45 =13 45 - 11 = 2 hrs 45 mim Option gives wrong outcomes Option B) 12 :00 + 2 14 00 hrs 14 - 11 = 3 hrs Option is giving correct outcome Option C) 12:00 + 2 :15 14 :15 - 11= 3 hrs 15 min Option gives wrong outcomes Option D) 12:00 +2:30 =14:30 14 : 30 - 11 = 3 hrs 30 mins Option gives wrong outcomes
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