A rectangular surface 3′ × 4′, has the lower 3 edge horizontal and 6′ below a free oil surface (sp. gr. 0.8). The surface inclination is 300 with the horizontal. The force on one side of the surface is (where, y = specific weight of water) ?
Correct answer: B. 48y
- A. 39.6y
- B. 48y
- C. 49.2y
- D. 58y
Explanation
The centroid is 5 ft below the oil surface because the 4-ft inclined length has a vertical rise of 2 ft from its lower edge at 6 ft depth. Thus F = 0.8γw(12)(5) = 48γw, giving option b.
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